Gill Broussard's Planet 7X Orbital Elements have been Reverse Engineered!

Gill Broussard is gaining popularity as a proponent of his own little “Planet X” theory based mostly on his own personal interpretation of various scriptures, but with popular “Nibiru” nuggets added in for flavor. He claims to be an amateur astronomer and he claims to have figured out the orbit of “Planet7X” even though he won’t explicitly state the orbital elements. He was interviewed about a week ago on John B Wells program, Caravan To Midnight:

Here’s Gill’s book about his “Planet 7X”:
www.danielholdings.com/news/gill-broussards-free-book-pdf/
He goes on for nearly 50 pages in his book about where his “Planet7X” will be at various points in time and what it will do to earth, but he never gives the orbital elements he calculated for it. And he clearly calculated orbital elements for it. He’s plugged them into Starry Night in order to create this diagram and many others throughout the book:
h.dropcanvas.com/nt2k7/planet7xperiheliondistance.jpg
So why doesn’t he just state the Keplerian elements so that others like me can observe his planet? After all, according to his own chart in the bottom left corner of page 39, it should currently be naked eye magnitude and has been for months (so where the hell is it, amateur astronomers all over the world would know about it by now). Well, if he did that then his claim would be easily falsifiable; anyone could simply point their telescopes at the coordinates he claims his planet is at and show whether or not there is a bright planet there or not (anything naked eye magnitude is blazingly bright to proper astrophotography rigs). As long as he keeps himself the sole source of the exact location he always has wiggle room when giving approximate locations (look between these constellations) so that he can excuse himself to say the reason no one has seen it is because they aren’t looking in quite the right location, etc.
He’s deliberately keeping the orbital elements secret, he knows what they are for the orbital charts he shows, he had to plug them into Starry Night himself. Unfortunately for him, because Starry Night shows the points of perihelion for displayed planets orbits, it is possible to measure the chart he shows and figure out the longitude of perihelion for the unknown planet based on the known longitudes of perihelion of Venus and Mercury (131.2 and 77.5 degrees respectively). The little straight lines popping out from each orbit shows the point of perihelion for each orbit. We expect to see 53.7 degrees of difference between Venus and Mercury, and if you measure the angle on the above image that is what you get. Measuring the angle of the point showed for his planet7x, we get a longitude of perihelion of about 81.96 degrees. We can also figure out the approximate perihelion distance from this chart; we know the perihelion distance of both Venus and Mercury and if you do the math you get an image scale of about 207 pixels per AU. That means his planet 7X has a perihelion distance of about 0.347 AU. He also says the orbital period is about 319 years on this orbit. That means the semi-major axis must be about 46.69 AU. Since we know the semi-major axis and the perihelion distance we can directly calculate the eccentricity (it equals e=1-(q/a)) and we get an answer of about 0.99257. His chart depicts an inclination from the ecliptic of about .02 degrees and depicts the ascending node as being near the point of perihelion, so we’ll set the argument of perihelion to 0 degrees and the longitude of ascending node to 81.96 so that will also equal the longitude of perihelion we measured as being 81.96 degrees. His book also explicitly says that the time of perihelion is February 17, 2016, which is JD 2457435.5. So that’s it! I’ve reverse engineered his orbital elements. They match extremely well with the charts he shows.
Perihelion feb 17 2016 – 2457435.5
Perihelion distance 0.3469 AU
Longitude of perihelion = 81.96 (measured)
Semi-major axis: 46.69 AU
e = 0.99257
inclination = 0.02
One thing though is that he shows a very close encounter between his planet7x and earth occurring on March 25/26. This doesn’t quite happen with the above orbit, though they’re relatively close. It appears that in order for that event to occur the longitude of perihelion would need to be about 5 degrees less, so about 76.96 degrees.
Plotting both positions from the two different longitude of perihelia shows a difference of a few degrees in the sky as currently observed from earth (about 4.5 degrees apart), but certainly gives the bounds on where it would have to be according to the various points of his book. In other words, a precise enough solution for a direct search for his planet. It’s either there or it’s not. I’ll take a look for it this weekend; it’s currently transiting the meridian at my location sometime around 4:20 am in the morning.
Dr. Astro

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